(x+1)^2-8(x+1)+15=0

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Solution for (x+1)^2-8(x+1)+15=0 equation: 



(x+1)^2-8(x+1)+15=0

We multiply parentheses

(x+1)^2-8x-8+15=0

We add all the numbers together, and all the variables

-8x+(x+1)^2+7=0

We move all terms containing x to the left, all other terms to the right

-8x+(x+1)^2=-7

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